# PTB 9th Class Physics Unit 2 “Kinematics” Solved Questions and Numericals Problems

View and Download the solved questions, solved numerical problems or 9th Class Physics notes of Chapter 2 “Kinematics” of Punjab Textbook Board. These 9th class physics notes of 2nd Chapter are according to the new syllabus (2013) of Punjab Boards including Lahore Board, Gujranwala Board, Sahiwal Board, Rawalpindi Board, Faisalabad Board, Multan Board, Bahawalpur Board, Federal Board, DG Khan Board and Sargodha Board. Students of 9th Class of all these board can facilitate from the physics notes given below. You can also download 9th Class Physics Chapter 2 Solved Questions and Numericals Problems.

### Unit 2: Kinematics

After studying this unit, the students will be able to: Describe using examples how objects can be at rest and in motion simultaneously. Identify different types of motion i.e. translatory, (linear, random, and circular); rotatory and vibratory motions and distinguish among them. Differentiate with examples between distance and displacement, speed and velocity.Differentiate with examples between scalar and vector quantities. Represent vector quantities by drawing. Define the terms speed, velocity and acceleration. Plot and interpret distance-time graph and speed-time graph. Determine and interpret the slope of distance-time and speed-time graph. Determine from the shape of the graph, the state of a body including at rest, moving with constant speed and moving with variable speed.

**9th Class Physics Chapter 2 Short Question Answers**

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**9th Class Physics Chapter 2 Solved Numericals**

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#### Correction and Comments about Numericals and Short Question Answers

**Numerical 2.9**

**Question Asked by Maria Khan**: The answer of numerical 2.9 of 2nd part where the distance is asked to find is, not coming correct.so please check this.your answer is 266.53m but through calculator is 296.14m.plz solve this query.

**Answer**: Actually, the value of 266m comes when you do not round off the value of acceleration (means a= -0.3331666875 m/s*s) and all other velocities. So your answer is also correct because you round off the value of acceleration. In exams I would say that write the value of distance 296m because this is the value you computed after rounding off and it is correct also.**Numerical 2.8**

**Problem :**Incomplete Numerical and missing page number 14.

**Remaining Part:**

0 = 6vi – 180

vi = 30m/s

Now calculating height reached by the ball

using formula 2as = vf2 – vi2

putting values in the above formula

s = (vf2 – vi2)/2a

s = (0 – 30*30)/2*9.8

s = 45m approx

Hence the height reached by the ball is 45 meters and the initial velocity is 30 m/s

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can you tell me formula of kmh square convert into ms

Multiply the km/h value with 1000 and divide by 3600 to convert it to m/s.

Thanks for solved numericals

plz plz upload 9 th class physics notes problems

Sir, I have a question that in Numerical#2.6 We have Done this(10*m/s)

So,(10*3600/1000)

So why Dont we have done this (10*1000/3600) because as the meter(m) is at upper side and the second(s) is at the lower side.

It would be Great if you email me. Thanks

it is because we are converting the unit (m/s) to (km/h). As km(kilometer) and h(hour) are larger quantities than m(meter) and s(second), so to convert small quantities to large quantities we divide and to convert large to small quantities we multiply. Now observe that m is numerator so dividing it by 1000 which is obvious, but s is in denominator so dividing it by 3600 would seems multiplying with 3600 because if you divide denominator, the dividing number would come in numerator.

if you wondering why 1000 and 3600 then your answer is:

1 km = 1000 m and 1 h = 3600 s

and if you wondering why we are converting it to other quantities, it is because for applying formula, we should use SI units.

thanx for providing us the numericals

in ch 2 numerical=2.4 how would we know that we have to use this formula(2gs=vf-vi) hum koi aur q nahi use kar saktey

mujhe samaj nahi ata kay kis question me hume kon sa formula use karna hai like in question 2.8 hum koi aurformula bhi to dal saktay the par humne h=vit+1/2gt q use kia plz reply me is bare me bohut tense aur is confusion ki waja se mujh se koi ch2 ka question nahi ho pata

You don’t have to use the some specific formula for each question. You can choose any formula, but you have to look that the variables you have and the variable you want to find is in your chosen formula. The answer would the same.

Sometime formula also depends on situation, but at this stage you do not have to worry about that.

PLZ ADD BIOLOGY NOTES FOR 9TH CLASS.. I NEED IT….

THNX SIR

the answer of numerical 2.9 of 2nd part where the distance is asked to find is, not coming correct.so plz check this.your answer is 266.53m but through calculator is 296.14m.plz solve this query.

Actually, the value of 266m comes when you do not round off the value of acceleration (means a= -0.3331666875 m/s*s) and all other velocities. So your answer is also correct because you round off the value of acceleration. In exams I would say that write the value of distance 296m because this is the value you computed after rounding off and it is correct also.

agr in notes sy exam ki tiyari ki jaye to success rate kia (%) hoga?

These are just numericals and short questions, for exams you have to do more.

nice i like it this notes sloved my difficulities

Amizing its very nice

ItS Goods

this notes helped me a lot a day after tomorow i am having physics paper plzz pray for me

why does the atmospheric pressure vary with hight?

Because of the density of gasses changes at different altitudes and heavy gases are attracted because of gravity, thus resulting in the change of atmospheric pressure.

thank u your notes are awesome

NICE

sir es page pe kuch nahi aa raha…

i dont know why!

kal mein ne apne Laptop se kiya tha sad aa raha tha nd abhi computer se kar rahi hoon toh kuch nahi aa raha…

sir plz kuch karein…

i’m getting soooo tensed!!

Refresh the page, or may be its some glitch in the browser.

greate work it has easier my life thanks

great work sir may ALLAH help you for this kind of help

ameen

I like it

owesum,

plz ch 6,7,8,9,10,or,11 k notes bhee upload karyn

These notes were very helpfull for me at the time when i lost my key book and had to give test after 2 hours thankU

Sir , I went through your notes and I liked them very much but i have some suggestions for you:

* the notes should not be handwritten.

*as i have read only the 1st chapter; some of its questions are incorrect such as q1.8 ,q1.9 etc.

I hope you dont mind. please reply

Yes, first of all we appreciate your suggestion. These notes are available for free and just for helping students, it may contains wrong answers due to mistakes. To convert these notes and rectify them we need more resources, which unfortunately we don’t have, because these notes are for free.

Yes, q 1.8 and q 1.9 have wrong answers,

The correct answers will be:

Answer 1.8 ) It is the measurement that an instrument shows when it should be showing zero.

Answer 1.9 ) By knowing the zero error, necessary correction can be made to find correct measurement. Otherwise our reading will be incorrect.

thank you very much,its very helpful for me ,grt work ,best of luck

Thanx sir! Awesome work

Notes are not avail as whenever webs open msg that server is timed out or address changed appear. Pl extend help

Notes are gr8 but whenever I open the msg server is timed out appear. Pl extend help

Can you please upload answers of MCQ’s of chapter no. 2?

plz chap 6 7 8 ke numerical upload kr dain

Sir i need ch 7,8,9 datsx is not here plz upload thatx chpter. Thanks

Kindly solve the numericals of 10th class some of them are quite tough. As a student they are difficult for us.

thank you so much your notes really awsome

can u plz explin q.8 short questions..plz reply soon thanxxx

these notes rvery helpful but can u plz upload notes of other subjects as well

Thannks, we will also upload the notes of Mathematics and Chemistry soon.

gra8 notes

For Problem 2.9, you used acceleration as 0.33m/s.I’d say you should use o.3332m/s because I solved and the answer was coming out all wrong.

You did this wrong too:

vf= vi + at

0= 26.667 – 0.3332t

0.3332t= 26.667

t= 26.667/0.3332=80.03 which rounded off will be 80 because 80.80 makes 81.

Thank you.

Yes you are absolutely right, but you cannot say that the above given answer is wrong. These little differences can be neglected and will not cost you any negative mark.

Well,I am in grade 8th and in our school,even a slightly wrong answer will cut your marks but still the notes were helpful.

Yes in school level every child is trained like this to make students cautious, but eventually you will understand about the difference between wrong and precision.

your effort is really awesome sir.All stuff is very nice n quite easy to understand.

sir kindly upload other chapters of physics 9th, chap 6,7,8,,, thanks for your courtesy sir.

Question 2.8 is not completely solved.

Page no 14 is missing, we will upload the remaining page soon.

upload it quickly….plzz

updated above

AOA,the solution of P2.8 was incomplete this numerical problem was done by wrong method so plz correct it,because i tally this frm book and these ans are, in step 1

the answer was 45m, and in 2nd step the ans was 30m/s

Yes there is a page missing, we will correct it soon.

r the notes gone :'( ? i cant see them today ~ mathar

Notes are still available, kindly refresh the page again.

Thanks 4 your notes.

ur site is sooo awsome….all numaricals r so eassy then my teacher tought to me….i really thank u for my hart….thank u

hmmm ur notes r really awesome and they r really helpful for me

thanks its very helpful.plz baki chapters and subjects k bhi notes provide ker dain.

Its good .